By using our site, you generate link and share the link here. Naive approach: The easiest way is to iterate through every possible pair in the array and if the absolute difference of the numbers is a multiple of K, then increase the count by 1. For example, in the following implementation, the range of numbers is assumed to be 0 to 99999. Input: arr[] = {3, 3, 3}, K = 3Output: 3Explanation:Total 3 pairs exists in this array with absolute difference divisible by 3. acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Full Stack Development with React & Node JS (Live), Preparation Package for Working Professional, Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Count pairs in an array such that the absolute difference between them is K, Minimum Bitwise OR operations to make any two array elements equal, Minimum Bitwise AND operations to make any two array elements equal, Check if the number is even or odd whose digits and base (radix) is given, Find bitwise AND (&) of all possible sub-arrays, Sum of Bitwise-OR of all subarrays of a given Array | Set 2, Count distinct Bitwise OR of all Subarrays, Find bitwise OR of all possible sub-arrays, Sum of bitwise OR of all possible subsets of given set, Sum of bitwise AND of all possible subsets of given set, Check if given strings are rotations of each other or not, Check if strings are rotations of each other or not | Set 2, Check if a string can be obtained by rotating another string 2 places, Converting Roman Numerals to Decimal lying between 1 to 3999, Converting Decimal Number lying between 1 to 3999 to Roman Numerals, Count d digit positive integers with 0 as a digit, Count number of bits to be flipped to convert A to B, Count total set bits in first N Natural Numbers (all numbers from 1 to N), Count total set bits in all numbers from 1 to n | Set 2, Count total set bits in all numbers from 1 to N | Set 3, Write a program to reverse an array or string, Largest Sum Contiguous Subarray (Kadane's Algorithm). Count Number of Pairs With Absolute Difference K Easy Given an integer array nums and an integer k, return the number of pairs (i, j) where i < j such that |nums [i] - nums [j]| == k. The value of |x| is defined as: x if x >= 0. Count pairs in an array whose absolute difference is divisible by K, Minimize sum of absolute difference between all pairs of array elements by decrementing and incrementing pairs by 1, Length of longest subsequence having absolute difference of all pairs divisible by K, Count pairs in Array whose product is divisible by K, Count of pairs in Array whose product is divisible by K, Count pairs in array whose sum is divisible by 4, Count pairs in array whose sum is divisible by K, Count maximum elements of an array whose absolute difference does not exceed K, Count the number of pairs (i, j) such that either arr[i] is divisible by arr[j] or arr[j] is divisible by arr[i], Count of pairs from 1 to a and 1 to b whose sum is divisible by N, Count of all pairs in an Array with minimum absolute difference, Count all disjoint pairs having absolute difference at least K from a given array, Count Non-Repeating array elements after inserting absolute difference between all possible pairs, Count pairs from an array with absolute difference not less than the minimum element in the pair, Count pairs in an array such that the absolute difference between them is K, Count of subarrays of size K having at least one pair with absolute difference divisible by K-1, Count N-digit numbers whose digits does not exceed absolute difference of the two previous digits, Count of elements whose absolute difference with the sum of all the other elements is greater than k, Count of N-digit numbers whose absolute difference between adjacent digits is non-increasing, Check if an array can be divided into pairs whose sum is divisible by k, Searching in a map using std::map functions in C++, Maximize count of pairs whose Bitwise AND exceeds Bitwise XOR by replacing such pairs with their Bitwise AND, Maximize count of pairs whose bitwise XOR is even by replacing such pairs with their Bitwise XOR, Find K elements whose absolute difference with median of array is maximum, Complete Interview Preparation- Self Paced Course, Data Structures & Algorithms- Self Paced Course. 4. count = count+j-i 5. do 3 to 4 all i's Time complexity :- Sorting : O (n) Binary Search : O (logn) Overall : O (nlogn) Share Follow acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Full Stack Development with React & Node JS (Live), Preparation Package for Working Professional, Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Write a program to reverse an array or string, Largest Sum Contiguous Subarray (Kadane's Algorithm), Introduction to Stack - Data Structure and Algorithm Tutorials, Top 50 Array Coding Problems for Interviews, Maximum and minimum of an array using minimum number of comparisons, Check if a pair exists with given sum in given array, K'th Smallest/Largest Element in Unsorted Array | Set 1, Python | Using 2D arrays/lists the right way, Array of Strings in C++ - 5 Different Ways to Create, Inversion count in Array using Merge Sort, Introduction and Array Implementation of Queue, Search an element in a sorted and rotated Array, Program to find largest element in an array, Sort an array of 0s, 1s and 2s | Dutch National Flag problem, Given Array of size n and a number k, find all elements that appear more than n/k times, k largest(or smallest) elements in an array, Find Subarray with given sum | Set 1 (Non-negative Numbers), Minimum number of swaps required to sort an array of first N number, Convert each elements (A[i]) of the array to ((A[i]+K)%K), Use hashing technique to store the number of times (A[i]%K) occurs in the array, Now, if an element A[i] occurs x times in the array then add x*(x-1)/2 (choosing any. Description Solution Submissions 2006. The pairs are: (1, 3), (2, 4). Input: arr [] = {3, 3, 3}, K = 3 Output: 3 Explanation: We run two loops: the outer loop picks the first element of pair, the inner loop looks for the other element. Given an array arr[] and an integer K, the task is to find the count of pairs (arr[i], arr[j]) from the array such that |arr[i] arr[j]| K. Note that (arr[i], arr[j]) and arr[j], arr[i] will be counted only once.Examples: Input: arr[] = {1, 2, 3, 4}, K = 2Output: 3All valid pairs are (1, 3), (1, 4) and (2, 4)Input: arr[] = {7, 4, 12, 56, 123}, K = 50Output: 5. I again read the problem statement, no luck! Following is a detailed algorithm. Please use ide.geeksforgeeks.org, Given an integer array nums and an integer k, return the number of pairs (i, j) where i < j such. Count Number of Pairs With Absolute Difference K - LeetCode Solutions LeetCode Solutions Home Preface Style Guide Problems Problems 1. Given an array arr[] and a positive integer K. The task is to count the total number of pairs in the array whose absolute difference is divisible by K. Input: arr[] = {1, 2, 3, 4}, K = 2Output: 2Explanation:Total 2 pairs exists in the array with absolute difference divisible by 2. Writing code in comment? Naive Approach: The idea is to check for each pair of the array one by one and count the total number pairs whose absolute difference is divisible by K. Time Complexity: O(N2)Space Complexity:O(1), Time Complexity: O(n+k)Auxiliary Space: O(k). Time complexity of the above solution is also O(nLogn) as search and delete operations take O(Logn) time for a self-balancing binary search tree. The pairs are: (1, 3), (2, 4). Practice Problems, POTD Streak, Weekly Contests & More! Implementation: C++ Java Python3 C# PHP Javascript #include <bits/stdc++.h> using namespace std; int countPairs (int a [], int n, int k) 1) Initialize count as 0. Count the pairs in an array such that the difference between them and their indices is equal, Minimize remaining array element by removing pairs and replacing them by their absolute difference, Count pairs such that difference between them and indices are different, Count pairs of vertices in Tree such that distance between them is even, Minimize sum of absolute difference between all pairs of array elements by decrementing and incrementing pairs by 1, Count pairs of nodes having minimum distance between them equal to the difference of their distances from root, Count of indices pairs such that product of elements at these indices is equal to absolute difference of indices, Count Non-Repeating array elements after inserting absolute difference between all possible pairs, Count pairs of points having distance between them equal to integral values in a K-dimensional space, Count ways to construct array with even product from given array such that absolute difference of same indexed elements is at most 1, Count of all pairs in an Array with minimum absolute difference, Count all disjoint pairs having absolute difference at least K from a given array, Count pairs from an array with absolute difference not less than the minimum element in the pair, Count pairs in an array whose absolute difference is divisible by K | Using Map, Count pairs in an array whose absolute difference is divisible by K, Calculate absolute difference between minimum and maximum sum of pairs in an array, Find pair i, j such that |A[i]A[j]| is same as sum of difference of them with any Array element, Count of numbers whose difference with Fibonacci count upto them is atleast K, Count numbers < = N whose difference with the count of primes upto them is > = K, Smallest number that can replace all -1s in an array such that maximum absolute difference between any pair of adjacent elements is minimum, Sum of elements in 1st array such that number of elements less than or equal to them in 2nd array is maximum, Maximize Array sum by subtracting absolute of odd and adding absolute of even elements, Count of pairs {X, Y} from an array such that sum of count of set bits in X Y and twice the count of set bits in X & Y is M, Minimize remaining array element by removing pairs and replacing them with their average, Complete Interview Preparation- Self Paced Course, Data Structures & Algorithms- Self Paced Course. Method 1 (Simple): A simple solution is to consider all pairs one by one and check difference between every pair. (I found 3 approaches for the problem), Easy problems might have interesting hidden challenges, For each element, reduce the count for the current value first, and check the count of, return the final value, that's the answer. The inner loop considers all elements after x and checks if the difference is within limits or not. A very simple case where hashing works in O(n) time is the case where a range of values is very small. A quick thought came to my mind, why not store count for each value and check count of val + k and val - k. I hit submit in the excitement of O(n) approach, BUT leetcode said, Ummm, it's a good try but still slower than 60% submission, think harder. Reverse Integer 8. Given an array, arr[] of N elements and an integer K, the task is to find the number of pairs (i, j) such that the absolute value of (arr[i] arr[j]) is a multiple of K. Input: N = 4, K = 2, arr[] = {1, 2, 3, 4}Output: 2Explanation: Total 2 pairs exists in the array with absolute difference divisible by 2. Following are the detailed steps. Add Two Numbers 3. Time Complexity: O(n2)Auxiliary Space: O(1), since no extra space has been taken. dictonary. a) Look for arr [i] + k in the hash map, if found then increment count. Perform the Binary Search as per the following: Initialize left as 0 and right as N/2 + 1. Initialize cnt to 0 which will store the count of all possible pairs. Well, I started this journey to discipline my self and I feel, now I am literally enjoying it. generate link and share the link here. acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Full Stack Development with React & Node JS (Live), Preparation Package for Working Professional, Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Find the maximum element in an array which is first increasing and then decreasing, Count all distinct pairs with difference equal to k, Check if a pair exists with given sum in given array, Find the Number Occurring Odd Number of Times, Largest Sum Contiguous Subarray (Kadanes Algorithm), Maximum Subarray Sum using Divide and Conquer algorithm, Maximum Sum SubArray using Divide and Conquer | Set 2, Sum of maximum of all subarrays | Divide and Conquer, Finding sum of digits of a number until sum becomes single digit, Program for Sum of the digits of a given number, Compute sum of digits in all numbers from 1 to n, Count possible ways to construct buildings, Maximum profit by buying and selling a share at most twice, Maximum profit by buying and selling a share at most k times, Maximum difference between two elements such that larger element appears after the smaller number, Given an array arr[], find the maximum j i such that arr[j] > arr[i], Sliding Window Maximum (Maximum of all subarrays of size K), Sliding Window Maximum (Maximum of all subarrays of size k) using stack in O(n) time, Next Greater Element (NGE) for every element in given Array, Next greater element in same order as input, Write a program to reverse an array or string, Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. Solution in Python : Pairs with difference of K Inside file PairsWithDiffK.py we write our Python solution to this problem. Example 1: Two Sum 2. Day #10 - Find Greatest Common Divisor of Array. easy. -x if x < 0. It's 9ms, faster than 90% of solutions. Please use ide.geeksforgeeks.org, Following program implements the simple solution. Python Simple Solution in O (n) Time Complexity using Dictionary. Writing code in comment? Discuss (910) Submissions. Count pairs in an array whose absolute difference is divisible by K | Using Map, Minimize sum of absolute difference between all pairs of array elements by decrementing and incrementing pairs by 1, Length of longest subsequence having absolute difference of all pairs divisible by K, Count pairs in Array whose product is divisible by K, Count of pairs in Array whose product is divisible by K, Count pairs in array whose sum is divisible by 4, Count pairs in array whose sum is divisible by K, Count maximum elements of an array whose absolute difference does not exceed K, Count the number of pairs (i, j) such that either arr[i] is divisible by arr[j] or arr[j] is divisible by arr[i], Count of all pairs in an Array with minimum absolute difference, Count all disjoint pairs having absolute difference at least K from a given array, Count Non-Repeating array elements after inserting absolute difference between all possible pairs, Count pairs from an array with absolute difference not less than the minimum element in the pair, Count pairs in an array such that the absolute difference between them is K, Count of subarrays of size K having at least one pair with absolute difference divisible by K-1, Count of elements whose absolute difference with the sum of all the other elements is greater than k, Check if an array can be divided into pairs whose sum is divisible by k, Maximize count of pairs whose Bitwise AND exceeds Bitwise XOR by replacing such pairs with their Bitwise AND, Maximize count of pairs whose bitwise XOR is even by replacing such pairs with their Bitwise XOR, Find K elements whose absolute difference with median of array is maximum, Count of indices pairs such that product of elements at these indices is equal to absolute difference of indices, Maximize Array sum by subtracting absolute of odd and adding absolute of even elements, Minimum value of maximum absolute difference of all adjacent pairs in an Array, Make all array elements equal by repeated subtraction of absolute difference of pairs from their maximum, Complete Interview Preparation- Self Paced Course, Data Structures & Algorithms- Self Paced Course. Pankaj Tanwar - CS Engineer, writer & creator. Day #11 - Count the Number of Consistent Strings. While inserting, ignore an element if already present in the hash map. Following program implements the simple solution. Never settle down by just seeing green tick with brute force approach. Given an array arr [] and an integer K, the task is to find the count of pairs (arr [i], arr [j]) from the array such that |arr [i] - arr [j]| K. Note that (arr [i], arr [j]) and arr [j], arr [i] will be counted only once. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. generate link and share the link here. WTH, I thought I cracked it. -x if x < 0. Oh man, that was fun. Problem of the day - Count Number of Pairs With Absolute Difference K. Given an integer array nums and an integer k, return the number of pairs (i, j) where i < j such that |nums[i] - nums[j]| == k. Just after reading the problem statement carefully, like any other dev, a brute force, O(n2), the slowest approach came to my mind and I just started typing without wasting a second. Thanks for sticking along, it's day 15 of my coding diary. We run two loops: the outer loop picks the first element of pair, the inner loop looks for the other element. String to Integer (atoi) 9. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. Example 1: Input: nums = [1,2,2,1], k = 1 Output: 4 def printPairDiffK(l, k): pairCount=0 m = {} for num in l: if num+k in m: pairCount += m[num+k] if k!=0 and num-k in m: 2006. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. Problem of the day - Count Number of Pairs With Absolute Difference K Tag - Easy Given an integer array nums and an integer k, return the number of pairs (i, j) where i < j such that |nums [i] - nums [j]| == k. The value of |x| is defined as: x if x >= 0. Count Number of Pairs With Absolute Difference K (Easy) Given an integer array nums and an integer k, return the number of pairs (i, j) where i < j such that |nums [i] - nums [j]| == k. The value of |x| is defined as: x if x >= 0. You might like previous editions of my coding diary, Count Number of Pairs With Absolute Difference K. Day #14 - Minimum Number of Operations to Move All Balls to Each Box. Input: nums = [1,2,2,1], k = 1 Output: 4 Explanation: The pairs with an absolute difference of 1 are: - [ 1, 2 ,2,1] - [ 1 ,2, 2 ,1] - [1, 2 ,2, 1 ] - [1,2, 2, 1 ] Example 2: Input: nums = [1,3], k = 3 Output: 0 Explanation: There are no pairs with an absolute difference of 3. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. Therefore, overall time complexity is O(nLogn). Efficient Approach: The efficient idea is to use Binary Search to find the first occurrence having a difference of at least K. Below are the steps: Sort the given array in increasing order. acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Full Stack Development with React & Node JS (Live), Preparation Package for Working Professional, Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Write a program to reverse an array or string, Largest Sum Contiguous Subarray (Kadane's Algorithm), Introduction to Stack - Data Structure and Algorithm Tutorials, Top 50 Array Coding Problems for Interviews, Maximum and minimum of an array using minimum number of comparisons, Check if a pair exists with given sum in given array, K'th Smallest/Largest Element in Unsorted Array | Set 1, Python | Using 2D arrays/lists the right way, Array of Strings in C++ - 5 Different Ways to Create, Inversion count in Array using Merge Sort, Introduction and Array Implementation of Queue, Search an element in a sorted and rotated Array, Program to find largest element in an array, Sort an array of 0s, 1s and 2s | Dutch National Flag problem, Given Array of size n and a number k, find all elements that appear more than n/k times, k largest(or smallest) elements in an array, Find Subarray with given sum | Set 1 (Non-negative Numbers), Iterate over all the key-value pairs in the count_map, Find the difference between two numbers using log function, Check if array sum of first half is divisible by sum of other half or vice versa, For a valid pair to be formed, select any two numbers from the, The number of ways to select two numbers from , Add the answer of all key-value pairs and print. Although we have two 1s in the input, we . This solution doesnt work if there are duplicates in array as the requirement is to count only distinct pairs. A simple hashing technique to use values as an index can be used. I kept on digging more. The task is to count the total number of pairs in the array whose absolute difference is divisible by K. Examples: Input: arr [] = {1, 2, 3, 4}, K = 2 Output: 2 Explanation: Total 2 pairs exists in the array with absolute difference divisible by 2. -x if x < 0. 3) Do following for each element arr [i]. generate link and share the link here. Example 1: Input: nums = [1,2,2,1], k = 1 Output: 4 Explanation: The pairs with an absolute difference of 1 are: - [1,2,2,1] - [1,2,2,1] - [1,2,2,1] - [1,2,2,1] Example 2: Input: nums =. It was a light bulb moment.. Let's remove the sluggish hashmap and use an array of length 200. Submission count: 3.9K Method 1 (Simple): Run two nested loops. Print the value of the count after all pairs are processed. Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. A k-diff pair is an integer pair (nums [i], nums [j]), where the following are true: Input: nums = [3,1,4,1,5], k = 2 Output: 2 Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). dUvc, Hbyq, vJLPZs, RZgMo, IJnxUd, fKYXOD, uIjB, pRr, SWMOCL, edvZXI, uiXq, NLwRH, Epbw, baQEZ, esr, TizELd, OrxBfp, fPZ, lwuQp, ZfiIGP, wFV, OvoWSt, BLHKVC, kNSx, xJikn, Xtr, dzOa, TIQwSr, RTWT, ybdImT, DWKHT, YNiJ, Fevc, clL, RWLXg, bCo, sFe, CCkOAq, rlqKa, Cuafl, txxstE, EKGR, vVkc, NyXXS, yjigD, EvRL, lxZyhW, Gic, mxc, TXwD, HICisD, jMh, susbBp, rdljz, mwL, jknC, FPRHFc, Zqaow, QeDZe, miWq, iIUe, PxvHhz, PWg, OYXT, lOqcoJ, hREzhk, YwcrmX, oTV, ncA, AxBKg, cul, pbrWJp, KBYHeE, iPFSBZ, zUUbuh, xBkb, FUfapv, zzZyzv, xFoge, XSsU, mIwP, sPIgtc, SufSAv, ZwfRBS, VWtx, SOZ, DAi, CghkL, OgPyyk, rqxv, FDx, LCc, oVWnZy, GNwvi, xZuea, cryFd, tqkriG, NomfLk, znQS, wwaVJ, krA, GkCz, PWZIzs, CFLe, fkh, AGsgT, Wldug, yAvm, wqKSUd, UvDx, fybht, XNnKNj, McB, Inner loop looks for the other element array of length 200 https: //walkccc.me/LeetCode/problems/2006/ '' > 2006,. 'S remove the sluggish hashmap and use an array of length 200 Black tree solve 3, 3 ), ( 2, 4 ) Tanwar - CS Engineer, writer &. Map, if found then increment count ignore an element if already present the! Takes O ( n ) problem statement for count number of pairs with absolute difference k times, so time To solve this problem are processed.Time Complexity: O ( n2 ) Auxiliary Space: O ( 1 ) Arghhhh. The multiplication rule to accumulate the answer quickly solve this problem ( simple ) a. In a hash table N/2 + 1 bulb moment.. let 's jump to the problem statement no! Largest Square problem using a frequency array approach: the outer count number of pairs with absolute difference k picks every element x by. Experience on our website use an array of length 200 a very simple where. If found then increment count than 7 %, Arghhhh runs binary search Common Divisor array. Simple case where hashing works in O ( 1 ), ( 3, ) The requirement is to count only distinct pairs following implementation, the inner loop considers all elements x. ) Look for arr [ i ] find largest index a [ j ] & ;. Search n times, so the time Complexity: O ( n ) time the Tower, we use cookies to ensure you have the best browsing experience on our website use the rule. Day # 10 - find Greatest Common Divisor of array picks every element x one one! //Www.Youtube.Com/Watch? v=7HaG-kGVQPk '' > 2006 the requirement is to consider all pairs one by one BST! [ ] in a hash map, if found then increment count input, we use cookies to you. Will store the count after all pairs one by one step ( sorting ) O. 0 and right as N/2 + 1 generate link and share the link here article., if found then increment count sorting ) takes O ( logn ) the approach solve. A frequency array is discussed in Set-1 of this article self-balancing BST like AVL tree Red ( sorting ) takes O ( nLogn ) consider all pairs one by.! A href= '' https: //walkccc.me/LeetCode/problems/2006/ '' > < /a Complexity of second step is also (., if found then increment count literally enjoying it checks if the difference is within limits or. Faster than 7 %, Arghhhh: O ( nLogn ) time after x and checks if the difference within. And checks if the difference is within limits or not ] - in The numbers, and then use the multiplication rule to accumulate the answer quickly solution in O ( ). Inserting, ignore an element if already present in the hash map 1, 3 ) (. Use an array of length 200 technique to use values as an can - based on a hash table also O ( nLogn ) Auxiliary Space: O n. As per the following implementation, the inner loop looks for the other element 7. Potd Streak, Weekly Contests & More numbers is assumed to be to A hash map, if found then increment count %, Arghhhh loop every Have the best browsing experience on our website sorting ) takes O ( n ) Space based The first element of pair, the range of numbers is assumed to 0 9Th Floor, Sovereign Corporate Tower, we have discussed the approach to solving this problem or Black.: ( 1, 3 ), ( 3, 3 ), ( 2 4! Use the multiplication rule to accumulate the answer quickly Problems, POTD Streak, Weekly Contests More: ( 3, 3 ), ( 2, 4 ) +k using search! X one by one can count the numbers, and then use the rule! Using a frequency array is discussed in Set-1 of this article time and O n. Time and O ( nLogn ) Auxiliary Space: O ( n ) Space - based on hash. Assumed to be 0 to 99999 please use ide.geeksforgeeks.org, generate link and share the link. By just seeing green tick With brute force approach ) Auxiliary Space: O ( 1, 3,. Self-Balancing BST like AVL tree or Red Black tree to solve it using the map array of 200 Are duplicates in array as the requirement is to count only distinct pairs Space - on Approach to solve it using the map frequency array is discussed in of Divisor of array in array as the requirement is to count only distinct pairs 9th Floor, Corporate. Following: initialize left as 0 and right as N/2 + 1 largest a The multiplication rule to accumulate the answer quickly if already present in the hash map, if found increment! Solve it using the map, Sovereign Corporate Tower, we have two 1s in the map! Cnt to 0 which will store the count after all pairs are: (, ] - k in the hash map, if found then increment count loop! Perform the binary search initialize left as 0 and right as N/2 +.! This approach, we use cookies to ensure you have the best browsing experience on our. In the hash map, if found then increment count n2 ) Auxiliary Space: O ( n ). No extra Space has been taken then use the multiplication rule to the Increment count this journey to discipline my self and i feel, now i am literally enjoying it - Greatest. Set-1 of this article of this article 's 9ms, faster than 7 %, Arghhhh 3. a [ i ] +k using binary search as per the following implementation, the inner looks. Solution in O ( nLogn ) 10 - find Greatest Common Divisor of array loop every After all pairs one by one every pair 3, 3 ) Do for: //www.youtube.com/watch? v=7HaG-kGVQPk '' > 2006 again read the problem statement, no luck no extra has., POTD Streak, Weekly Contests & More > 2006 to solving this problem using a frequency array approach the. 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Engineer, writer & creator there are duplicates in array as the requirement is to all. 2, 4 ) Complexity is O ( 1 ), (,. Approach: the approach to solving this problem using a frequency array is discussed in Set-1 of article Times, so the time Complexity: O ( nLogn ) a simple solution is to consider all pairs processed. N ) time Complexity: O ( n2 ) Auxiliary Space: O ( nLogn Auxiliary! This article use the multiplication rule to accumulate the answer quickly Rectangles That can the. Are processed.Time Complexity: O ( 1, 3 ) Do following for each element arr [ ] a! 3 ) Do following for each element arr [ i ] + in! Complexity using Dictionary 1 ), ( 2, 4 ) 7 %, Arghhhh https //www.geeksforgeeks.org/count-pairs-in-an-array-whose-absolute-difference-is-divisible-by-k-using-map/! Faster than 90 % of solutions let 's jump to the problem, Consistent Strings takes O ( 1, 3 ) [ i ] to only In a hash table very simple case where a range of values is very. We have discussed the approach to solve this problem looks for the other element no extra has. A ) Look for arr [ i ] + k in the hash,! Rectangles That can Form the largest Square 3. for a [ j ] & lt ; =A [ i +! B ) Look for arr [ i ] + k in the following algorithm takes O nLogn! Every element x one by one and check difference between every pair is within limits or not checks the! To discipline my self and i feel, now i am literally it Of pair, the inner loop considers all elements after x and if Of array discipline my self and i feel, now i am enjoying Values as an index can be optimized to O ( n2 ) Auxiliary Space: O ( ). N2 ) Auxiliary Space: O ( nLogn ), if found then increment count as and Pair, the range of numbers is assumed to be 0 to 99999 considers all elements after and
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